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144=2x^2+10x+12
We move all terms to the left:
144-(2x^2+10x+12)=0
We get rid of parentheses
-2x^2-10x-12+144=0
We add all the numbers together, and all the variables
-2x^2-10x+132=0
a = -2; b = -10; c = +132;
Δ = b2-4ac
Δ = -102-4·(-2)·132
Δ = 1156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1156}=34$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-34}{2*-2}=\frac{-24}{-4} =+6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+34}{2*-2}=\frac{44}{-4} =-11 $
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